New PDF release: Integer Programming

By Stanisław Walukiewicz (auth.)

ISBN-10: 9048140684

ISBN-13: 9789048140688

ISBN-10: 9401579458

ISBN-13: 9789401579452

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Download e-book for iPad: Integer Programming by Stanisław Walukiewicz (auth.)

'Et moi, . .. , so j'avait su remark en revenir, One provider arithmetic has rendered the je n'y serais element al! e. ' human race. It has placed logic again Jules Verne the place it belongs, at the topmost shelf subsequent to the dusty canister labelled 'discarded non­ The sequence is divergent; as a result we can be sense'.

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13) by h1" > 0 we get v 1-h 1kwr >L 0. 13) W 1 -W, ~ >L 0 fori= 1, ... , m. 5. 5. 33 BOUNDED VARIABLES Linear programming problems with bounded variables v(P) = max{cxJAx = b,p ~ x ~ (P) d} quite often arise in branch-and-bound methods. The bounds x1 ~ p1 can be easily transformed to the standard form x1 ~ 0 by substitution of xj = x1 -p1 for j = 1, ... , n. Therefore, we can consider the problem v(P) = max{cxJAx = b, 0 ~ x ~ d}. (P) If A has m linearly independent rows, then P may be solved by the simplex method by including x ~ d into the constraints, which results in a problem with m+n constraints and 2n variables.

Hok ... XBi hto ... hi} "' htt ... XBr hro ... h,J ... hrk ... The zero column contains the basic feasible solution x 81 = h10 for i = 1, ... , m, while x 0 = XBo = h00 is the value of the objective function for this basic feasible solution. The zero row corresponds to the objective function of P and its elements hoi> j E R, are called the simplex multipliers (of a given basic feasible solution). 11) is called the pivot (element). It is easy to verify that in the simplex algorithm all calculations are carried on in the tabular form using in Step 4 the following rules: (1) Divide the rth row by the pivot element hrk· (2) Multiply the new rth row by h;k and subtract it from the ith row, i = 0, 1, ...

7) takes the form Xe1 = h01 - Lh x Lh x i 11 1 , 11 1 - = 0, 1, ... , m. jeR, jeR 1 Since x 1 = d1 for j e R 2 , the basic solution is xBI = hto- L h d =g 11 1 10 , i = 1, ... 14) jeR, and x 1 = 0 for j e R 1 • This solution is feasible if 0 ~ Kto i = 1 , ... , m. 3. (Optimality Conditions). 14) is an optimal solution toP ~f (i) 0 ~ Kto ~ (ii) h 0 1 ~ 0 (iii) h 01 ~ 0 dBi for i = 1 ... 3 that, in general, we get a better feasible basic solution if we introduce into the basis a nonbasic variable x" such that if k e R 1 , then ho,.

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