By Tarek Ahmed PhD PE, Nathan Meehan
, Pages i,iii
, Page iv
, Page ix
Chapter 1 - good checking out Analysis
, Pages 1-226
Chapter 2 - Water Influx
, Pages 227-279
Chapter three - Unconventional gasoline Reservoirs
, Pages 281-432
Chapter four - functionality of Oil Reservoirs
, Pages 433-483
Chapter five - Predicting Oil Reservoir Performance
, Pages 485-539
Chapter 6 - advent to more advantageous Oil Recovery
, Pages 541-585
Chapter 7 - monetary Analysis
, Pages 587-649
Chapter eight - monetary Analysis
, Pages 651-660
Chapter nine - Professionalism and Ethics
, Pages 661-682
, Pages 683-688
, Pages 689-702
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Additional resources for Advanced Reservoir Management and Engineering
125) CHAPTER 1 Well Testing Analysis 45 No-Flow Boundary p pi t1 t2 t3 No-Flow Boundary t4 rw r (a) p vs. r p Pressure At radius “r” r t1 t2 t3 (b) p vs. 23 Semisteady-state flow regime. where Eq. 126) where A 5 drainage area, ft2 Combining Eq. 127) • the reservoir pressure declines at a higher rate with increasing fluid production rate; the reservoir pressure declines at a slower rate for reservoirs with higher total compressibility coefficients; the reservoir pressure declines at a lower rate for reservoirs with larger pore volumes.
Combining Eq. 110) gives: 162:5 3 103 Qg μB g pwf 5 pi 2 kh ! 896 ! 120) or ð162:5 3 103 ÞQg μBg pwf 5 pi 2 kh ! ! 121) γ or, equivalently, in terms of dimensionless pressure drop: pwf 5 pi 2 ! 0 3 106 Solution Step 1. 5 hours by using the p approximation method and compare it with the exact solution. 13 is repeated below for convenience. 3 ft is producing at a constant flow rate of 2000 Mscf/ day under transient flow conditions. The initial reservoir pressure (shut-in pressure) is 4400 psi at 140 F.
Calculate ψD by applying Eq. 111): ψD 5 0:5½lnðtD Þ 1 0:80907 5 0:5½lnð279 365:1Þ 1 0:80907 5 6:6747 ZT p or Bg 5 0:00504 Step 2. Calculate ψD : Step 3. Solve for Eq. 118) Fetkovich (1973) suggested that at high pressures above 3000 psi (p . 22. Imposing Fetkovich’s condition on Eq. 119) CHAPTER 1 Well Testing Analysis 43 Again, this method is limited only to applications above 3000 psi. When solving for pwf, it might be sufficient to evaluate the gas properties at pi. 22 Plot of 1/μBg vs.
Advanced Reservoir Management and Engineering by Tarek Ahmed PhD PE, Nathan Meehan